y=((x^2)/2)+(x/3)

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Solution for y=((x^2)/2)+(x/3) equation: 


x in (-oo:+oo)

y = (x^2)/2+x/3 // - (x^2)/2+x/3

y-((x^2)/2)-(x/3) = 0

y-1/2*x^2-1/3*x = 0

DELTA = (-1/3)^2-(-1/2*4*y)

DELTA = 2*y+1/9

2*y+1/9 = 0

2*y+1/9 = 0 // - 1/9

2*y = -1/9 // : 2

y = -1/9/2

y = -1/18

DELTA = 0  <=>  t_1 = -1/18

x = 1/3/(-1/2*2) i y = -1/18

x = -1/3 i y = -1/18

( x = ((2*y+1/9)^(1/2)+1/3)/(-1/2*2) or x = (1/3-(2*y+1/9)^(1/2))/(-1/2*2) ) i y > -1/18

( x = -((2*y+1/9)^(1/2)+1/3) or x = (2*y+1/9)^(1/2)-1/3 ) i y > -1/18

y+1/18 > 0

y+1/18 > 0 // - 1/18

y > -1/18

x in { -1/3, -((2*y+1/9)^(1/2)+1/3), (2*y+1/9)^(1/2)-1/3 }

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